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0=x^2-10x+18.75
We move all terms to the left:
0-(x^2-10x+18.75)=0
We add all the numbers together, and all the variables
-(x^2-10x+18.75)=0
We get rid of parentheses
-x^2+10x-18.75=0
We add all the numbers together, and all the variables
-1x^2+10x-18.75=0
a = -1; b = 10; c = -18.75;
Δ = b2-4ac
Δ = 102-4·(-1)·(-18.75)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-5}{2*-1}=\frac{-15}{-2} =7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+5}{2*-1}=\frac{-5}{-2} =2+1/2 $
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